Error during sending mail

Question

I try to send mail via python. I got a function:

def mail():
    fromaddr = 'mymail@gmail.com'  
    toaddrs  = 'targetmail@o2.pl'  
    msg = 'There was a terrible error that occured and I wanted you to know!'  


    # Credentials (if needed)  
    username = 'mymail@gmail.com'  
    password = 'password'  

    # The actual mail send  
    server = smtplib.SMTP('smtp.gmail.com:587')  
    server.ehlo()
    server.starttls()
    server.ehlo()  
    server.login(username,password)  
    server.sendmail(fromaddr, toaddrs, msg)  
    server.quit() 

When I try to execute this function it whows me WinError 10060. Error text below:

Traceback (most recent call last): 
File "C:\python-factory\ServiceChecker\main\mainBlock.py", line 75, in <module>  mail()
File "C:\python-factory\ServiceChecker\main\mainBlock.py", line 65, in mail server =   smtplib.SMTP('smtp.gmail.com:587')  
File "C:\Python34\Lib\smtplib.py", line 242, in __init__ (code, msg) = self.connect(host, port)
File "C:\Python34\Lib\smtplib.py", line 321, in connect self.sock = self._get_socket(host, port, self.timeout)
File "C:\Python34\Lib\smtplib.py", line 292, in _get_socket self.source_address)
File "C:\Python34\Lib\socket.py", line 509, in create_connection raise err
File "C:\Python34\Lib\socket.py", line 500, in create_connection sock.connect(sa)
TimeoutError: [WinError 10060]

I don't know where is problem... i tried many mail servers (gmail,o2,wp,) all of them returned the same error. I tried also other available solutions in the internet to send mail via pyython.... the same problem...

Please help

Answer 1

According to your posted backtrace, you are failing at the line

server = smtplib.SMTP('smtp.gmail.com:587')  

I've run that line and it works for me. The clue is in the TimeoutError. I believe you are having networking problems and the code itself is fine.

You do have an extra call to ehlo but as it stands you are not getting that far.

Additionally, it would probably be better to pass the port number as a separate argument, rather than using a colon to split it. E.g.

server = smtplib.SMTP(host='smtp.gmail.com', port=587)

The documentation for smptlib is here: https://docs.python.org/2/library/smtplib.html