I try to open a video stream from a RTSP server into a JAVA application. First I tried to run this example :
package uk.co.caprica.vlcj.test.streaming;
import uk.co.caprica.vlcj.player.MediaPlayerFactory;
import uk.co.caprica.vlcj.player.headless.HeadlessMediaPlayer;
import uk.co.caprica.vlcj.test.VlcjTest;
/**
* An example of how to stream a media file using RTSP.
* <p>
* The client specifies an MRL of <code>rtsp://@127.0.0.1:5555/demo</code>
*/
public class StreamRtsp extends VlcjTest {
public static void main(String[] args) throws Exception {
if(args.length != 1) {
System.out.println("Specify a single MRL to stream");
System.exit(1);
}
String media = args[0];
String options = formatRtspStream("127.0.0.1", 5555, "demo");
System.out.println("Streaming '" + media + "' to '" + options + "'");
MediaPlayerFactory mediaPlayerFactory = new MediaPlayerFactory(args);
HeadlessMediaPlayer mediaPlayer = mediaPlayerFactory.newHeadlessMediaPlayer();
mediaPlayer.playMedia(media,
options,
":no-sout-rtp-sap",
":no-sout-standard-sap",
":sout-all",
":sout-keep"
);
// Don't exit
Thread.currentThread().join();
}
private static String formatRtspStream(String serverAddress, int serverPort, String id) {
StringBuilder sb = new StringBuilder(60);
sb.append(":sout=#rtp{sdp=rtsp://@");
sb.append(serverAddress);
sb.append(':');
sb.append(serverPort);
sb.append('/');
sb.append(id);
sb.append("}");
return sb.toString();
}
}
But I have always the same result : Specify a single MRL to stream
https://i.sstatic.net/8iX0O.png
Even if I delete this section :
if(args.length != 1) {
System.out.println("Specify a single MRL to stream");
System.exit(1);
}
Can you help me please ?
Sounds like you're not actually passing an argument to the program, which it expects from this line:
String media = args[0];
If you don't want to pass an argument, just change it to:
String media = "(location of rtsp to stream)";
...and delete the if statement above it as you already have.