my Domainname from input is:
example.com
curl $data
gives me this, always different:
between <span></span>
is the domain name.
1. <span>example.com</span>
2. <span>www.example.com</span>
3. <span>http://example.com</span>
4. <span>https://example.com</span>
5. <span>https://example.com/</span>
6. <span>https://example.com/categories</span>
7. <span><b>www</b>.<b>example</b>.<b>com</b></span>
8. <span><b>www</b>.<b>example.com</b></span>
9. <span>Not included</span>
the professionals have a good solution for me? fals one is found should be stopped.
My current code fails unfortunately. :-(
$dname = array($d1, $d2, $d3, $d4, $d5, $d6, $d7, $d8, $d9);
$pos = strpos($data, $dname);
if ($pos !== false) {
echo 'YES';
} else {
echo 'NO'
}
I personally would use regex:
preg_match_all('~<span>(.*)</span>~Ui',$data,$domains);
print_r($domains[1]);
That would give you list of domain names.
Or in your case, you could use function called strip_tags()
, this one would simply remove span
tags, and leave what was inside. Then you could simply explode("\n",$stripped_string);
Aafter that, you can use function in_array()
that would check if given domain is in array or not, or... array_diff()
, that would compare array with given and return elements that are not in there.
For example:
$data = <curl_result>;
preg_match_all('~<span>(.*)</span>~Ui',$data,$domains); // this finds all domains in span tags
$domains = array_map('trim',$domains[1]); // this rewrites results and removes blank spaces
$seeking = array('domain1.com','domain2.com');
foreach($seeking as $needle){
if(in_array($needle,$domains) !== false)
echo "Domain $needle was found!<br />";
else
echo "Domain $needle was not found!<br />";
}