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gomuxgorilla

How to call a route by its name from inside a handler?


How do I properly refer to route names from inside handlers?
Should mux.NewRouter() be assigned globally instead of standing inside a function?

func AnotherHandler(writer http.ResponseWriter, req *http.Request) {
    url, _ := r.Get("home") // I suppose this 'r' should refer to the router
    http.Redirect(writer, req, url, 302)
}

func main() {
    r := mux.NewRouter()
    r.HandleFunc("/", HomeHandler).Name("home")
    r.HandleFunc("/nothome/", AnotherHandler).Name("another")
    http.Handle("/", r)
    http.ListenAndServe(":8000", nil)
}

Solution

  • You have the method mux.CurrentRoute() that returns the route for a given request. From that request, you can create a subrouter and call Get("home")

    Example: (play: http://play.golang.org/p/Lz10YUyP6e)

    package main
    
    import (
            "fmt"
            "net/http"
    
            "github.com/gorilla/mux"
    )
    
    func HomeHandler(writer http.ResponseWriter, req *http.Request) {
            writer.WriteHeader(200)
            fmt.Fprintf(writer, "Home!!!\n")
    }
    
    func AnotherHandler(writer http.ResponseWriter, req *http.Request) {
            url, err := mux.CurrentRoute(req).Subrouter().Get("home").URL()
            if err != nil {
                    panic(err)
            }
            http.Redirect(writer, req, url.String(), 302)
    }
    
    func main() {
            r := mux.NewRouter()
            r.HandleFunc("/home", HomeHandler).Name("home")
            r.HandleFunc("/nothome/", AnotherHandler).Name("another")
            http.Handle("/", r)
            http.ListenAndServe(":8000", nil)
    
    }