After an exception, keep on running

Question

For example:

 try
{
   Task1();
   Task2();
   Task3();
}
catch (Exception ex)
{
}

Right now if an exception occurs in Task1(), the code in Task2 and Task2 method does not run. The program stops.

How could I make it so when an exception occurs, the code / methods that below it would keep on running to the end.

Thanks

Answer 1

An exception moves execution to the end of the try block and into the catch block. To do what you want, you'd have to use separate try/catch blocks:

try
{
   Task1();
}
catch (Exception ex)
{
}

try
{
   Task2();
}
catch (Exception ex)
{
}

try
{
   Task3();
}
catch (Exception ex)
{
}

You could put your tasks in a collection (provided they all have the same signature) and loop, but the net effect would be the same:

var tasks = new Action[] {Task1, Task2, Task3};
foreach(var task in tasks)
{
    try
    {
       task();
    }
    catch (Exception ex)
    {
    }
}