Here is just a test prototype :
#include <iostream>
#include <string>
using namespace std;
int main()
{
int a=10;
char b='H';
string c="Hamza";
cout<<"The value of a is : "<<a<<endl;
cout<<"The value of b is : "<<b<<endl;
cout<<"The value of c is : "<<c<<endl<<endl;
cout<<"address of a : "<<&a<<endl;
cout<<"address of b : "<<&b<<endl;
cout<<"address of c : "<<&c<<endl;
return 0;
}
Why the address of variable 'b', which is of character type, not printing?
The <<
operator in your code is overloaded in C++ 11. It doesn't conflict with any of other types like int
or string
, but it takes pointer to char
which if used can produce undesired results.
You can do it like:-
cout << static_cast<void*>(&b)