There is a code of simple program. In constructor, super()
is called without extends to the super class, I can not understand what will does this in this situation?
public class Student {
private String name;
private int rollNum;
Student(String name,int rollNum){
super(); //I can not understand why super keyword here.
this.name=name;
this.rollNum=rollNum;
}
public static void main(String[] args) {
Student s1 = new Student("A",1);
Student s2 = new Student("A",1);
System.out.println(s1.equals(s2));
}
}
Every class that doesn't explicitly extend another class implicitly extends java.lang.Object
. So super()
simply calls the no-arg constructor of Object.
Note that this explicit call is unnecessary since the compiler would add it for you. You only need to add a super()
call in a constructor when you want to invoke a superclass constructor with arguments.