I am currently calculating pi and the script I'm using doesn't stop after a certain point and, since Python loses your input after a certain point, I was wondering how I could save all I calculated. Here's the script that i'm using: EDIT: i was still new to python after finding this, tweaking it, and woundering how to save, i have since learned the obvios sultion of saving to to a file.
def calcPi():
q, r, t, k, n, l = 1, 0, 1, 1, 3, 3
while True:
if (4*q+r-t < n*t):
yield n
nr = 10*(r-n*t)
n = ((10*(3*q+r))//t)-10*n
q *= 10
r = nr
else:
nr = (2*q+r)*l
nn = (q*(7*k)+2+(r*l))//(t*l)
q *= k
t *= l
l += 2
k += 1
n = nn
r = nr
import sys
pi_digits = calcPi()
i = 0
for d in pi_digits:
sys.stdout.write(str(d))
i += 1
if i == 40:
print("")
i = 0
The only way to do this that I am aware of is to write the output to a file. The modified code below opens a file pi_out.txt, writes the first hundred digits of pi to it and then closes the file at the end.
import sys
def calcPi():
q, r, t, k, n, l = 1, 0, 1, 1, 3, 3
while True:
if 4*q+r-t < n*t:
yield n
nr = 10*(r-n*t)
n = ((10*(3*q+r))//t)-10*n
q *= 10
r = nr
else:
nr = (2*q+r)*l
nn = (q*(7*k)+2+(r*l))//(t*l)
q *= k
t *= l
l += 2
k += 1
n = nn
r = nr
pi_digits = calcPi()
pi_out = open('pi_out.txt','w')
i = 0
j = 0 #number of digits of pi to find and output
for d in pi_digits:
sys.stdout.write(str(d))
print >> pi_out, d
i += 1
j += 1
if i == 40: print(""); i = 0
if j == 100: break #breaks loop after finding appropriate digits of pi
pi_out.close() #IMPORTANT Always close files
Alternatively you could do this directly inside the function and have it output inside the file each time you call yield.