Android detect missed call

Question

I am attempting to have my application recognize when there is a missed call. I have created a BroadcastReceiver that detects when the phone's state has changed. Here is my onReceive() method:

public void onReceive(Context context, Intent intent) {
    boolean ringing = false, callReceived = false;
    String callerPhoneNumber = "";
    String state = intent.getStringExtra(TelephonyManager.EXTRA_STATE);

    if (TelephonyManager.EXTRA_STATE_RINGING.equals(state)) {
        ringing = true;
        Bundle bundle = intent.getExtras();
        callerPhoneNumber= bundle.getString("incoming_number");

        if (ringing) {
            Toast.makeText(context, "Phone call from: " + callerPhoneNumber, Toast.LENGTH_LONG).show();
        }
    }

    if (TelephonyManager.EXTRA_STATE_OFFHOOK.equals(state)) {
        callReceived = true;
        Toast.makeText(context, "Call received.", Toast.LENGTH_LONG).show();
    }

    if (TelephonyManager.EXTRA_STATE_IDLE.equals(state)) {
//          Toast.makeText(context, "Phone is idle", Toast.LENGTH_LONG).show();

        if (ringing) {
            Toast.makeText(context, "ringing is true", Toast.LENGTH_LONG).show();
        }

//          if (ringing && !callReceived) {
//              Toast.makeText(context, "It was A MISSED CALL from : " + callerPhoneNumber, Toast.LENGTH_LONG).show();
//          }
    }

The issue I am having is the application detects when the phone is ringing, sets ringing to true, and shows the appropriate toast message. However, when the phone's state is idle, it does not enter the if (ringing) statement to show the ringing is true toast message. However, if I comment in the toast message just above it, it will correctly print that the Phone is idle.

Is it possible that ringing is being reset to false somewhere between the phone ringing and the phone becoming idle again?

Answer 1

You can not store any "state" information in a broadcast receiver. If you want to do a comparison old state / new state, I think you can use a service.