I'm total newbie in programming...thanks in advance for all those who will answer me.. I'm trying to print the columns starting from a search. Actually my excel is composed like this:
| | Header | Header | Header | Header |
|Header|Server 1|Server 2|Server 3|Server 4|
|Header| Data | Data | Data | Data |
|Header| Data | Data | Data | Data |
|Header| Data | Data | Data | Data |
This is my code but the output is not what I'm looking for....
fo_set_parse = xls.parse(:header_search => ['Server'], :clean => true)
fo_set_parse.each do |row|
row.each do |key,value|
if value != nil
puts "#{value}"
end
end
end
I'd like to print in the same excel style starting from a "Server" search..The number of "Server" change every time, so I'can't use something like
1.upto(xls.last_column) do |col|
server1 = xls.cell(2,col)
server2 = xls.cell(3,col)
server3 = xls.cell(4,col)
server4 = xls.cell(5,col)
puts "#{server1}\t #{server2}\t #{server3}\t #{server4}\t"
end
Any help?
I'm not familiar with roo (and at a quick glance, it doesn't seem like there are many examples to pull from), but how about:
data_row_definitions = {
:data_a => 2, # i.e. data_a is stored in row 2 for all servers
:data_b => 3,
:data_c => 4,
}
server_columns = 2.upto(xls.last_column) # or whatever columns the servers are listed
server_columns.map do |server_col|
data_for_server = Hash[
data_row_definitions.map do |data_name, row|
cell_value = xls.cell(row, server_col)
[data_name, cell_value]
end
]
end
With a table like:
| |Server 1|Server 2|Server N|
| dataA | 1| 3| 7|
| dataB | 10| 35| 14|
| dataC | 100| 95| 28|
(I would imagine) You would get the data structure:
[
{
"dataA" => 1,
"dataB" => 10,
"dataC" => 100,
},
{
"dataA" => 3,
"dataB" => 35,
"dataC" => 95,
},
{
"dataA" => 7,
"dataB" => 14,
"dataC" => 28,
},
]
And should work for however many N
servers/columns you have due to every sever/column being enumerated in the server_columns
variable.