Flex tree control drag drop .item position

Question

just facing a difficulty with tree control drag drop..
Suppose i have tree with drag-drop enabled. I want to which node(id) is droped inside which node.

1]if i drag "Cat1" node inside "Cat3",i want to identify ids of siblings of "cat1",and "cat3".

2]in general i want to know the ids of current element being moved along with
its new parent and new position and save these postions.

3] Also "cat4" when moved outside "cat3",i want know its position and its siblings id.

<mx:XML id="treeDP">
        <node label="Categories">
          <node label="Cat1" id="1" isBranch="true"/>            
          <node label="Cat2" id="2" isBranch="true"/>

           <node label="Cat3" id="3" isBranch="true">
             <node label="Cat4" id="4" isBranch="true"/>
         </node>          
        </node>
</mx:XML>

    <mx:Tree id="compBalanced" 
        width="420" height="439" 
        dataProvider="{treeDP}" 
        showRoot="false"
        labelField="@label"
        doubleClickEnabled="true"
        dragEnabled="true" 
        dropEnabled="true" 
        dragDrop="onDragDrop(event)"            
            />

Answer 1

I've meet a problem like this, when I had to check the node wich receive the children. To get the node parent, I'd used this :

public function getObjectTarget() : Object {
   var dropData : Object = tree.mx_internal::_dropData as Object;
   if (dropData.parent != null) {
      return dropData.parent;
   } else {
          // if there is not parent (root of the tree), I take the root directly
      var renderer : IListItemRenderer = tree.indexToItemRenderer(0);
      return renderer.data;
   }

hope this will help some one