I am using PsychoPy and I would like to print the position of my mouse when it has been clicked.
The actual printing of the position needs to be placed inside a while loop. Using the code below, when I click I get more than one output lines, which print the same positions. I would like to have only one output printing for each click.
This is the code I am using:
#!/usr/bin/env python2
from psychopy import visual, core, event
from pyglet.gl import *
width = 600
height = 600
myWin = visual.Window([width,height], color='white',units='pix',monitor='testMonitor')
#This will set the windows units (pixels) to GL units
glMatrixMode(GL_PROJECTION)
glLoadIdentity()
glOrtho(0, width, 0, height, -1, 1)
glMatrixMode(GL_MODELVIEW)
glLoadIdentity()
glEnable(GL_BLEND)
glBlendFunc(GL_ZERO, GL_SRC_COLOR)
myMouse = event.Mouse() # will use myWin by default
while True:
#Triangle left
glColor3f(1.0, 0.0, 0.0)
glBegin(GL_TRIANGLES)
glVertex3f(150, 550, 1)
glVertex3f(50, 350, 1)
glVertex3f(250, 350, -1)
glEnd()
if myMouse.getPressed()[0]:
myMouse.clickReset()
print myMouse.getPos()
myWin.flip()
core.quit()
Is there something wrong I am doing? Should the 'frame rate' of the while loop be changed?
I've not used the module, but it seems like mouse events are thrown for mouse raises as well.
You'll need to
Store the mouse state for next time
Each iteration, test whether the mouse state for button 0 has gone up → down
The mouse state is returned by myMouse.getPressed
.
So something like:
oldMouseIsDown = False
while True:
...
mouseIsDown = myMouse.getPressed()[0]
myMouse.clickReset()
if mouseIsDown and not oldMouseIsDown:
print myMouse.getPos()
oldMouseIsDown = mouseIsDown