I am trying to use a variable in a foreach loop but I am getting strange results. The first foreach loop work fine but gives a notice of a undefined variable and in the second version there is no notice but it only returns the last item in the array.
$formats = array(
'application/x-mpegurl' => 'hls',
'video/webm' => 'webm',
'video/mp4' => 'mp4',
'video/ogg' => 'ogg',
'video/flash' => 'flash',
);
// Works perfectly but there a undefined variable $source
foreach( $formats as $format => $src ){
if ( !empty( $src ) ) {
$source .= '<source type="' . $format . '" src="' . $src . '">';
}
}
echo $source;
// Returns only the last item in the variable but there is no undefined variable
foreach( $formats as $format => $src ){
$source2 = '';
if ( !empty( $src ) ) {
$source2 .= '<source type="' . $format . '" src="' . $src . '">';
}
}
echo $source2;
I have googled for solutions have not found any.
Define $source
an d $source1
before the loops start.
$source = "";
// loop starts here
Complete code:
$source = "";
foreach( $formats as $format => $src ){
if ( !empty( $src ) ) {
$source .= '<source type="' . $format . '" src="' . $src . '">';
}
}
echo $source;
$source2 = '';
foreach( $formats as $format => $src ){
if ( !empty( $src ) ) {
$source2 .= '<source type="' . $format . '" src="' . $src . '">';
}
}
echo $source2;