I am starting with an array of sources
$scope.sources = [
{
"type": "register",
"name": "Register 1",
"balance": 100
},
{
"type": "register",
"name": "Register 2",
"balance": 100
},
{
"type": "register",
"name": "Register 3",
"balance": 200
},
{
"type": "office",
"name": "Change Drawer",
"balance": 200
},
{
"type": "office",
"name": "Safe",
"balance": 500
}
];
I'm successfully loading the options
<div class="form-group">
<label>Transfer <strong>{{amount(count, start, selectedItem.balance) | currency}}</strong> To:</label>
<select id="transferTo" class="form-control" ng-model="form.to" ng-options="item.name for item in sources | filter:{type:'office'}">
<option value="">-- Select a Source --</option>
</select>
</div>
I've tried using a $timeout
function to select it after it works, but it doesn't pass back the correct value to my function
$timeout(function () {
$('#transferTo').val('1');
}, 200);
How would I set the "Safe" as the default option selected when the form loads?
You will need to set a value on your scope that you're setting ng-model equal to:
$scope.form.to = $scope.sources[4];
If your list (sources) is dynamic you can filter the array like this, which will return an array (but leave your array untouched).
filterFilter($scope.sources, {name: 'Safe'})