Alternating 1's and 0's in a table - Python

Question

I want to make a table of alternating 1's and 0's using for statements and lists for a given number of rows and columns (similar to the code below). Any ideas as to how I would do this?

#fill elements in left and right columns with ones

ROWS = m
COLUMNS = n
table = []

for i in range(COLUMNS):
    if i ==0 or i == (COLUMNS-1):
        column = [1] * ROWS
    else:
        column = [0] * ROWS
    table.append(column)

for i in range(ROWS):
    for j in range(COLUMNS):
        print(table[j][i], end=" ")
    print()

Answer 1

Maybe you want something like this:

ROWS = 5
COLUMNS = 5
table = [[1 if i%2==0 else 0 for i in range(COLUMNS)] for j in range(ROWS)]

for row in table:
for cell in row:
    print (cell, end=' ')
print()
1 0 1 0 1
1 0 1 0 1
1 0 1 0 1
1 0 1 0 1
1 0 1 0 1

OR maybe:

table = [[(i+j)%2 for i in range(COLUMNS)] for j in range(ROWS)]
0 1 0 1 0
1 0 1 0 1
0 1 0 1 0
1 0 1 0 1
0 1 0 1 0