1st query:
SELECT date_trunc('day', date1) as date, COUNT(*) AS count_a
FROM table_a GROUP BY date
result:
date count_a
2014-04-01 00:00:00.0 1011642
2014-04-02 00:00:00.0 309048
2nd query:
SELECT date_trunc('day', date1) as date, COUNT(*) AS count_b
FROM table_b GROUP BY date
result:
date count_b
2014-04-01 00:00:00.0 2342
2014-04-02 00:00:00.0 43432
I'd like to get:
date count_a count_b
2014-04-01 00:00:00.0 1011642 2342
2014-04-02 00:00:00.0 309048 43432
Is this possible?
A simple UNION ALL should make it possible.
SELECT date1 date, SUM(a) count_a, SUM(b) count_b
FROM (
SELECT DATE_TRUNC('day', date1) date1, 1 a, 0 b FROM table_a
UNION ALL
SELECT DATE_TRUNC('day', date1) date1, 0 a, 1 b FROM table_b
) z
GROUP BY date;
EDIT: Here's an SQLfiddle.