Dear Masters of The Command Line,
I have a directory tree for which I want to generate a file that contains on two entries per line: full path for each file and the corresponding privileges of said file.
For example, one line might contain:
/v1.6.0.24/lib/mylib.jar -r-xr-xr-x
The best way to generate the left hand column there appears to be find. However, because ls doesn't seem to have a capability to either read a list of filenames or take stdin, it looks like I have to resort to a script that does this for me. ...Cumbersome.
I was sure I've seen people somehow get find to run a command against each file found but I must be daft this morning as I can't seem to figure it out!
Anyone?
In terms of reading said file there might be spaces in filenames, so it sure would be nice if there was a way to get some of the existing command-line tools to count fields right to left. For example, we have cut. However, cut is left-hand-first and won't take a negative number to mean start the numbering on the right (as seems the most obvious syntax to me). ... Without having to write a program to do it, are there any easy ways?
Thanks in advance, and especial thanks for explaining any examples you may provide!
Thanks, RT
GNU findutils 4.2.5+:
find -printf "$PWD"'/%p %M\n'