I have the following union and it works correct:
#pragma pack(1)
...
union
{
uint8_t opcode;
struct
{
uint8_t z : 3;
uint8_t y : 3;
uint8_t x : 2;
};
}opcode;
The size of the union is exactly one byte, according to
printf ("%zu\n", sizeof opcode);
The problem takes place when I try to make a union from the bit-field there:
union
{
uint8_t opcode;
struct
{
uint8_t z : 3;
union
{
uint8_t y : 3;
struct
{
uint8_t p : 2;
uint8_t q : 1;
};
}y;
uint8_t x : 2;
};
}opcode;
The result of
printf ("%zu\n", sizeof opcode);
is 3 bytes. Of course I can workaround this with macros but it is it possible at all?
No, it isn't possible to have structs that are fractions of a byte big.
Rationale:
It must be possible to make a pointer to a struct, and the smallest adressable unit is 1 byte.
Note: This limitation exists in all compilers that I know. I don't know whether it is actually mandated by the C standard.