How to sum 2 numbers digit by digit with pseudo code?
Note: You don't know the length of the numbers - if it has tens, hundreds, thousands... Units should be add to units, tens to tens, hundreds to hundreds..... If there is a value >= 10 in adding the units you need to put the value of that ten with "the tens"....
I tried
Start
Do
Add digit(x) in A to Sum(x)
Add digit(x) in B to Sum(x)
If Sum(x) > 9, then (?????)
digit(x) = digit(x+1)
while digit(x) in A and digit(x) in B is > 0
I am lost with that.....
Please help!
Try this,
n = minDigit(a, b) where a and b are the numbers.
let sum be a number.
m = maxDigit(a,b)
allocate maxDigit(a,b) + 1 memory for sum
carry = 0;
for (i = 1 to n)
temp = a[i] + b[i] + carry
// reset carry
carry = 0
if (temp > 10)
carry = 1
temp = temp - 10;
sum[i] = temp
// one last step to get the leftover carry
if (digits(a) == digits(b)
sum[n + 1] = carry
return
if (digits(a) > digits(b)
toCopy = a
else
toCopy = b
for (i = n to m)
temp = toCopy[i] + carry
// reset carry
carry = 0
if (temp > 10)
carry = 1
temp = temp - 10;
sum[i] = temp
Let me know if it helps