How do you put results on a single line? (In bash)

Question

So I made this file and I am currently running it within a bash shell and it lists fine, however each result is placed on its own individual line. I was wondering how I would make the same program, but make it place the results laterally, one result after another.

x=0;while [ $x -le  256 ]
do
t=$(tput sgr 0);r=$(tput setaf $x);echo "${r} $x ${t}";((x=$x+1))
done

Answer 1

How i understand, u need something like this:

x=0;while [ $x -le  256 ]
do
t=$(tput sgr 0);r=$(tput setaf $x);echo -n "${r} $x ${t}";((x=$x+1))
done

U forgot to use echo -n (no new line)

Formatted version with columns:

#!/bin/bash

t=$(tput sgr 0)
for x in {0..255}; do
  printf "%s%4s${t}" "$(tput setaf $x)" $x
  if [ $((x % 15)) -eq 0 ]; then  echo;  fi;
done