Matching function literals with quasiquotes in Scala

Question

This question is similar in motivation to my previous question (although it's about a problem I ran into in a different context).

I can pattern match on a function literal pretty easily without quasiquotes:

import scala.reflect.macros.Context
import scala.language.experimental.macros

object QQExample {
  def funcDemo(f: Int => String) = macro funcDemo_impl
  def funcDemo_impl(c: Context)(f: c.Expr[Int => String]) = {
    import c.universe._

    f.tree match {
      case Function(ps, body) => List(ps, body) foreach println
      case _ => c.abort(
        c.enclosingPosition,
        "Must provide a function literal."
      )
    }

    c.literalUnit
  }
}

Which works like this:

scala> QQExample.funcDemo((a: Int) => a.toString)
List(val a: Int = _)
a.toString()

Now suppose I want to use quasiquotes to do the same kind of match more flexibly. The following will also match on that function, and prints what we'd expect.

case q"($x: $t) => $body" => List(x, t, body) foreach println

But if I want to specify the type in the pattern, it doesn't match:

case q"($x: Int) => $body" => List(x, body) foreach println

And none of the following even compile:

case q"$p => $body"      => List(p,  body) foreach println
case q"($p) => $body"    => List(p,  body) foreach println
case q"..$ps => $body"   => List(ps, body) foreach println
case q"(..$ps) => $body" => List(ps, body) foreach println

Is it possible to specify the type of a parameter when matching on a function literal with quasiquotes, or to match on an unknown number of parameters?

Answer 1

With latest paradise plugin for 2.10 and in vanilla 2.11 you can do it this way:

val q"(..$args) => $body" = f.tree

I've just tested it out with paradise example project with following Macros.scala:

import language.experimental.macros
import scala.reflect.macros.Context

object Macro {
  def apply(f: Any): Any = macro impl
  def impl(c: Context)(f: c.Expr[Any]) = { import c.universe._
    val q"(..$args) => $body" = f.tree
    println(s"args = $args, body = $body")
    c.Expr(q"()")
  }
}

And Test.scala:

object Test extends App {
  Macro((x: Int) => x + 1)
}

You can read in more about handling of function trees with quasiquotes in corresponding chapter of quasiquote guide.