Can I call a overloaded constructor of the same class in C#?

Question

I know that I can do that with ': this()' but if I do that the overloaded constructor will be excecuted first and I need it to be executed after the the constructor that will call it . . . . Is complicated to explain let me put some code:

Class foo{
    public foo(){
       Console.WriteLine("A");
    }
    public foo(string x) : this(){
       Console.WriteLine(x);
    }
}

///....

Class main{
    public static void main( string [] args ){
       foo f = new foo("the letter is: ");
    }
}

In this example the program will show

A 
the letter is:

but what I want is

the letter is: 
A

There is a 'elegant way' to do this? I would prefer to avoid extracting the constructor actions to separated method and call them from there.

Answer 1

Yes, you can do this pretty easily (unfortunately):

class foo {
    public foo( ) {
        Console.WriteLine( "A" );
    }
    public foo( string x ) {
        Console.WriteLine( x );

        var c = this.GetType( ).GetConstructor( new Type[ ] { } );
        c.Invoke( new object[ ] { } );
    }
}

class Program {
    static void Main( string[ ] args ) {
        new foo( "the letter is: " );
    }
}