I'm using a custom dialog in onpostexecute method in AsyncTask, it is being popped twice. When the user clicks on a button the dialog has to be closed, this seems to work fine.
Can someone shed some light on why it is being called twice ?
@Override
protected void onPostExecute(Void result) {
super.onPostExecute(result);
if (pDialog != null) {
pDialog.dismiss();
}
try {
if (responseFromServer.contains("x")) {
// Pop up to create password
final Dialog dialog = new Dialog(getActivity());
dialog.setContentView(R.layout.dialog_password);
dialog.setTitle("Title...");
dialog.setCancelable(false);
final TextView etpassword = (TextView) dialog.findViewById(R.id.etpassword_dialog);
final Button btnpassword = (Button) dialog
.findViewById(R.id.btnsavepassword_dialog);
btnpassword.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
if (etpassword.getText().toString().length() == 0) {
Toast.makeText(getActivity(), "Enter password", Toast.LENGTH_SHORT)
.show();
} else if (etpassword.getText().toString().length() < 6) {
Toast.makeText(getActivity(),
"Password should contain minimmum 6 characters",
Toast.LENGTH_SHORT).show();
} else {
dialog.dismiss();
}
}
});
if (!dialog.isShowing()) {
dialog.show();
}
}
else {
Toast.makeText(getActivity(), "Unexpected error occurred. Please try again",
Toast.LENGTH_SHORT).show();
}
} catch (Exception e) {
Log.v("Main FRagment FB async::::::", e.getMessage());
}
}
You can write following condition before display a custom dialog,
if ( !dialog.isShowing() )
{
dialog.show();
}