I have a simple script test.sh
#!/bin/bash
echo $0
When I run the following from csh terminal:
bash -c 'test.sh'
Then the output is test.sh
But when I run:
bash -c 'source test.sh'
The output is bash
Does anybody know how to print the script name in this case?
#!/bin/bash
declare -r SCRIPT_NAME=$(readlink -f ${BASH_SOURCE[0]})