In MySQL how to write SQL to search for words in a field?

Question

create table tbl (
  id int,
  comment varchar(255),
  primary key (id)
);

insert into tbl (id, comment) values ('1', 'dumb,');
insert into tbl (id, comment) values ('2', 'duuumb,');
insert into tbl (id, comment) values ('3', 'dummb');
insert into tbl (id, comment) values ('4', 'duummb');
insert into tbl (id, comment) values ('5', 'very dumb person');

select comment, soundex(comment) 
from tbl;

Result:

+------------------+------------------+
| comment          | soundex(comment) |
+------------------+------------------+
| dumb,            | D510             |
| duuumb,          | D510             |
| dummb            | D510             |
| duummb           | D510             |
| very dumb person | V6351625         |
+------------------+------------------+

I want to find all rows containing 'dumb', including all typos and variations, anywhere in the field.

select comment 
from tbl
where soundex(comment) like '%D510%'

This fails to get the final row #5, how can I also get that row? If there is a better solution than soundex() that would be fine.

Answer 1

This will work for your particular example:

select comment 
from tbl
where soundex(comment) like '%D510%' or comment like '%dumb%';

It won't find misspellings in the comment.

EDIT:

You could do something like this:

select comment
from tbl
where soundex(comment) = soundex('dumb') or
      soundex(substring_index(substring_index(comment, ' ', 2), -1)  = soundex('dumb') or
      soundex(substring_index(substring_index(comment, ' ', 3), -1)  = soundex('dumb') or
      soundex(substring_index(substring_index(comment, ' ', 4), -1)  = soundex('dumb') or
      soundex(substring_index(substring_index(comment, ' ', 5), -1)  = soundex('dumb');

A bit brute force.

The need to do this suggests that you should consider a full text index.