I know that it is maybe not the most beautiful thing to partialy deling with view in model, but for now I would like to solve my problem this way.
in my models.py for one class I define:
def admin_image(self):
return '<img src="/media/%s"/>' % self.thumbnail.photo
admin_image.allow_tags = True
BUT I would like that instead of hard coded /media/ there MEDIA_URL will be used, but have no idea how to call it. I am newbie to django, so please be kind :)
in my settings.py I defined:
PROJECT_ROOT_PATH = os.path.abspath(os.path.join(os.path.dirname(__file__), os.path.pardir))
MEDIA_ROOT = os.path.join(PROJECT_ROOT_PATH, 'media/')
MEDIA_URL = '/media/'
and in admin.py I use readonly_fields = ['admin_image']
and then I use it in list_display and fieldsets.
OK. I think I got it. Anyway comments how to deal with it better will be apriciated.
in models.py:
from django.conf import settings
def admin_image(self):
return '<img src="'+settings.MEDIA_URL+'%s"/>' % self.thumbnail.photo
admin_image.allow_tags = True