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bashshellunixawknawk

Printing lines according to their columns in shell scripting

i know it is very basic question but im total new in shell scripting

i a txt file called 'berkay' and content of it is like

03:05:16 debug blablabla1
03:05:18 error blablablablabla2
05:42:14 degub blabblablablabal
06:21:24 debug balbalbal1

I want to print the lines whose second column is error so the output will be

03:05:18 error blablablablabla2

I am thinking about something like " if nawk { $2}" but i need help.

Solution

  • With this for example:

    $ awk '$2=="error"' file
03:05:18 error blablablablabla2

    Why is this working? Because when the condition is true, awk automatically performs its default behaviour: {print $0}. So there is no need to explicitly write it.