I have been looking for an error in my code since an hour. This was the error:
Writing:
if(isset(($_POST['to'])))
instead of
if(isset($_POST['to']))
I don't get why is this extra pair of brackets causing an Internal Server Error.
I don't think putting brackets around a variable never changes its value. I mean,
$a = $b;
$c = ($b);
$a==$c; //True
I am curious as to know why is it an error?
Thank you.
EDIT:
The above error was occurring for normal variable also.
This is because isset
is not a function but a language construct; as such, its definition can be found in the language parser.
T_ISSET '(' isset_variables ')' { $$ = $3; }
It only expects one pair of braces; passing another pair will cause a parse error.