I have written some code in OCaml which performs actions similar to the following
let rec main() =
DO STUFF...
let print_time() =
let time = Unix.localtime (Unix.time()) in
let hour = string_of_int (time.Unix.tm_hour) in
let minute = string_of_int (time.Unix.tim_min) in
print_string ("\n Time -- " ^ hour ^ ":" ^ minute)
in
Lwt.bind(Lwt_unix.sleep 30.)
(fun() -> (print_time(); main();)
;;
main();;
This code runs perfectly in the toplevel, however it seems that the times are being printed to a buffer and not immediately printed to the screen. All of the times in the buffer print to the screen at once when I give the toplevel another command.
How can I correct this issue so that the times are printed to the toplevel every time print_time()
is called and not when I give the toplevel a command?
Example: If I run the program and then wait 2 minutes before I type something into the toplevel I get the following output. If I don't type anything into the toplevel then I only receive the first time message.
# #use "this_program";;
Time -- 12:03
# let x = 1;;
time -- 12:03
time -- 12:04
time -- 12:04
time -- 12:05
time -- 12:05
val x : int = 1
#
Also, this "loop" only works once (main()
will not recursively call itself) in native compiled code, I have no idea how to correct that.
I would try adding flush stdout
after your call to print_string
.