Here is my attempt:
case class A(val a: A, val b: Int){
override def toString() = b.toString
}
lazy val x: A = A(y, 0)
lazy val y: A = A(z, 1)
lazy val z: A = A(x, 2)
The problem comes when trying to do anything with x; causing x to be evaluated starts off a circular evaluation going through x, y, z and ends in a stack overflow. Is there a way of specifying that val a should be computed lazily?
You need to make A.a
itself lazy.
You can do it by turning it into a by name parameter that is used to initialize a lazy field:
class A(a0: => A, val b: Int){
lazy val a = a0
override def toString() = b.toString
}
object A {
def apply( a0: => A, b: Int ) = new A( a0, b )
}
You could also do the same using a helper class Lazy
:
implicit class Lazy[T]( getValue: => T ) extends Proxy {
def apply(): T = value
lazy val value = getValue
def self = value
}
It has the advantage that you code is pretty much unchanged except for changing a: A
into a: Lazy[A]
:
case class A(val a: Lazy[A], val b: Int){
override def toString() = b.toString
}
Note that to access the actual value wrapped in Lazy
, you can either use apply
or value
(as in x.a()
or x.a.value
)