Python IndentationError - Codecademy: Python basics: Pyg Latin 9/12

Question

Here's my code:

pyg = 'ay'

original = raw_input('Enter a word:')
word = original.lower()
first = word[0]


if len(original) > 0 and original.isalpha():
        if first in 'aeiou':
    print 'vowel'
            else:
                print "consonant"
        else:
            print "empty"

and here's the confusing error message:

File "python", line 10 print 'vowel(' ^) IndentationError: unindent does not match any outer indentation level

It says this (") is the problem. I can't really continue my learning of Python without my step.

Answer 1

pyg = 'ay'

original = raw_input('Enter a word:')
word = original.lower()
first = word[0]

if len(original) > 0 and original.isalpha():
    if first in 'aeiou':
        print 'vowel'
    else:
        print "consonant"
else:
    print "empty"

Indentation (the number of spaces from the left before each line of code) is important in Python. Each if and else must have the same indentation.

For instance...

if 1 == 1:

    else:

...will not work, because there's 0 spaces before if and there's 4 spaces before else. So each else that belongs to a if statement must be aligned.