Process lines of text with bash

I'm saving a file with dates and file names with this structure:

date1 name1
date2 name2
...
dateN nameN

Afterwards I'm reading the file with the while command and trying to compare if the date field is equal to a date given. If the date is the same, I'm saving the name and then printing it.

while read line
do
    if [ ‘$($line | cut -c 1-10)’ == ‘$(date +%Y-%m-%d)’ ]
    then
        name=$($linea | cut -c 12-100)
    fi
    echo $name
done < archivos.txt

After executing the script, the console is giving me every date into the file with the 'command not found' error.

Thanks in advance :-)

Solution

Your approach is interesting, but it may be easier to skip the use of a while loop and use awk all together, giving the date as parameter:

awk '$1~d {print $2}' d=$(date +%Y-%m-%d) archivos.txt

$1~d {print $2} if the first field matches the date given, print the 2nd field.
d=$(date +%Y-%m-%d) pass today's date to awk.

Sample

$ cat a
2014-01-28 hello
2014-01-28 byetwo
2014-02-28 bye
2014-01-29 bye

$ awk '$1~d {print $2}' d=$(date +%Y-%m-%d) a
hello
byetwo