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c++c++14

What is the difference between auto and decltype(auto) when returning from a function?


I rarely see decltype(auto) but when I do it confuses me because it seems to do the same thing as auto when returning from a function.

auto g() { return expr; }
decltype(auto) g() { return expr; }

What is the difference between these two syntaxes?


Solution

  • auto follows the template argument deduction rules and is always an object type; decltype(auto) follows the decltype rules for deducing reference types based on value categories. So if we have

    int x;
    int && f();
    

    then

    expression    auto       decltype(auto)
    ----------------------------------------
    10            int        int
    x             int        int
    (x)           int        int &
    f()           int        int &&