Ok. The problem is I am working on a website that you can easily up-vote or down-vote a certain image/video etc. Now the thing that came up was SENDING the request. I can process most php things and so on so forth, I can also do database requests; but, how do I send a request to my php page? I want it to send from the main page and it will do it without refreshing the page. Also, I tried adding it to a "form", the user clicks the button and it submits, but I need a "id" variable added WITH the request. Now, I know I will need some jquery and Ajax, but I have NO CLUE were to start on that. Here is what I have for my first page:
<form action="vote.php">
<input type="image" src="imgs/1.png" name="1" alt="<?php echo $sub; ?>" />
<input type="image" src="imgs/2.png" name="2" alt="NOT" />
<input type="text" value="<?php echo $id; ?>" name="id" hidden />
</form>
Now, the vote page:
<?php
require_once('inc/dbConnect.php');
if (empty($id)) {
$error = "Which photo to vote?"
}
// Receive vote count, is it UP or DOWN?
// save in variable
// do a check and add it to database, <- I can do this part.
?>
HTML:
<form action="vote.php">
<button type="button" name="vote" value="up">Upvote</button>
<button type="button" name="vote" value="down">Downvote</button>
<input type="hidden" name="image" value="filename_or_unique_id_of_img.jpg">
</form>
jQuery:
form.find('button').on('click',function(){
var form,url,data;
form = $('form');
url = form.attr('action');
data = 'voted='+$(this).val()+'&image='+image;
$.ajax({
url:url,
data:data,
type:'POST',
success:function(data){
alert(data) //'Thanks for voting!'
}
})
})
PHP:
$vote = $_POST['vote'];
$image = $_POST['image'];
//stuff with database
echo 'Thanks for voting!';