I need to write a function that finds the successors of a given coordinate. By successors I mean, 3 kinds: horizontal, vertical and diagonal.
Horizontal its easy: match the row number of the coordinate to the row number of the next one and it is the horizontal successor of that coordinate.
Vertical: Same match the column number of the coordinate to the column number of the next one and that determines if its a vertical successor
Diagonal: Not sure. A square has only 2 digonals so if my coordinate is on the diagonal of the square, I need to verify this first, if it is then I need to find its successors. How do I do this?
1) verify a point is on the diagonal of a square? and
2) If it is on the diagonal find its successor?
For example in this grid:
00, 01, 02, 03, 04, 05, 06, 07, 08
10, 11, 12, 13, 14, 15, 16, 17, 18
20, 21, 22, 23, 24, 25, 26, 27, 28
30, 31, 32, 33, 34, 35, 36, 37, 38
40, 41, 42, 43, 44, 45, 46, 47, 48
50, 51, 52, 53, 54, 55, 56, 57, 58
60, 61, 62, 63, 64, 65, 66, 67, 68
70, 71, 72, 73, 74, 75, 76, 77, 78
80, 81, 82, 83, 84, 85, 86, 87, 88
Thanks
Find points on diagonals :-
if(i==j) {
left diagonal
} if(i==n-j-1) {
right diagonal
}