I need some help in Shell scripting.
I have a folder with single-letter folder names starting with 1 and ending with the small letter z: [1-9A-Za-z].
Now, I want to rename the folders to its hexadecimal value:
1 to 31 ... z to 7A.
I wanted to fix this with a for loop, but now I'm stuck here. I had never programmed with Shell, but with C and ASM.
[Edit]: Open your Terminfo folder. On OS X (10.9.1): /usr/share/terminfo.
There you can see hex values.
Now, on my iPhone, they are in single ASCII characters. Therefore the terminal can't find any file.
In any appropriate directory, you can try:
$ mkdir terminfo
$ cd terminfo
$ mkdir {0..9} {a..z}
$ ls
0 3 6 9 c f i l o r u x
1 4 7 a d g j m p s v y
2 5 8 b e h k n q t w z
$ for d in ?; do mv "$d" $(printf "%2X" "'$d'"); done
$ ls
30 33 36 39 63 66 69 6C 6F 72 75 78
31 34 37 61 64 67 6A 6D 70 73 76 79
32 35 38 62 65 68 6B 6E 71 74 77 7A
$
If you use echo mv instead of just mv, you can see the operations the shell does. You can use %2x in place of %2X to get names like 7a, which matches what I see in /usr/share/terminfo on my machine (but the file system is case-preserving and case-insensitive, so the upper-case should work). You might also consider using ln -s instead of mv; that way, you have both the old names and the new names available, so old code and new code should be happy.
Tested on Mac OS X 10.9.1 Mavericks.