UPDATED THE SOLUTION::: IT IS WORKING NOW
I have created a controller with join query. Now I want to include controller to actionCreate function and show data into text filed in form.
public function actionCreate()
{
$model=new Grndetail;
if (isset($_POST['Grndetail'])) {
$model->attributes=$_POST['Grndetail'];
if ($model->save())
$this->redirect(array('view','id'=>$model->id));
}
$grndata = $this->GrnData1();
$model->im_grnnumber = $grndata['im_grnnumber'];
$this->render('create',array('model'=>$model, 'grndata'=>$grndata,));
}
public function GrnData1()
{
$sql = Yii::app()->db->createCommand()
->select('t.im_grnnumber, t.im_purordnum, r.pp_purordnum, r.cm_code, r.pp_quantity, r.pp_unit, r.pp_unitqty, r.pp_purchasrate, p.cm_description, p.cm_code')
->from('im_grnheader t')
->join('pp_purchaseorddt r', 't.im_purordnum = r.pp_purordnum')
->join('cm_productmaster p', 'p.cm_code = r.cm_code')
//->where('id=:id', array(':id'=>$id))
->order('im_grnnumber DESC')
->queryRow();
return $sql;
}
<?php echo $form->textField($model,'im_grnnumber'); ?>
Is anything I am missing. How can I view the data as value in form when I am creating something.
UPDATED THE SOLUTION::: IT IS WORKING NOW
You should change your program as
public function GrnData1(){
$sql = Yii::app()->db->createCommand()->setFetchMode(PDO::FETCH_OBJ) // change it
->select('t.im_grnnumber, t.im_purordnum, r.pp_purordnum, r.cm_code, r.pp_quantity, r.pp_unit, r.pp_unitqty, r.pp_purchasrate, p.cm_description, p.cm_code')
->from('im_grnheader t')
->join('pp_purchaseorddt r', 't.im_purordnum = r.pp_purordnum')
->join('cm_productmaster p', 'p.cm_code = r.cm_code')
->order('im_grnnumber DESC')
->queryRow();
Return $sql; // write here return statement
}
Now you can access your data like this
echo $form->textField($model,'im_grnnumber', array('value'=>$grndata->im_grnnumber));
Hope, It will help you.
Thanks