I am trying to replace an array of characters from within an NSString.
For example if we have this string:
NSString *s = @"number one and two and three";
NSArray *A1 = [NSArray arrayWithObjects:@"one",@"two",@"three", nil];
NSArray *A2 = [NSArray arrayWithObjects:@"1",@"2",@"3", nil];
I need to replace all members of that string found within A1 with the corresponding members of A2.
NSString
has an instance method called stringByReplacingOccurencesOfString:
see the Apple Documentation for NSString for help on the actual method - code wise you could try the below code.
NSString *s = @"number one and two and three";
NSArray *A1 = [NSArray arrayWithObjects:@"one",@"two",@"three", nil];
NSArray *A2 = [NSArray arrayWithObjects:@"1",@"2",@"3", nil];
NSLog(@"s before : %@", s);
// Logs "s before : number one and two and three"
// Lets check to make sure that the arrays are the same length first if not forget about replacing the strings.
if([A1 count] == [A2 count]) {
// Goes into a for loop for based on the number of objects in A1 array
for(int i = 0; i < [A1 count]; i++) {
// Get the object at index i from A1 and check string "s" for that objects value and replace with object at index i from A2.
if([[A1 objectAtIndex:i] isKindOfClass:[NSString class]]
&& [[A2 objectAtIndex:i] isKindOfClass:[NSString class]]) {
// If statement to check that the objects at index are both strings otherwise forget about it.
s = [s stringByReplacingOccurrencesOfString:[A1 objectAtIndex:i] withString:[A2 objectAtIndex:i]];
}
}
}
NSLog(@"s after : %@", s);
// Logs "s after : number 1 and 2 and 3"
As noted in comments this code could return "bone" as "b1". To get around this you could I suppose replace your arrays with:
NSArray *A1 = [NSArray arrayWithObjects:@" one ",@" two ",@" three ", nil];
NSArray *A2 = [NSArray arrayWithObjects:@" 1 ",@" 2 ",@" 3 ", nil];
Note I all I have done is added in the spaces so if you had "bone" it will not replace it to "b1".