I have the following function (Viviani's curve):
Phi = @(t)[ cos(t)^2, cos(t)*sin(t), sin(t) ]
Just a check that it's valid:
s = linspace(0,T,1000);
plot3(cos(s).^2, cos(s).*sin(s), sin(s));
How to derivate the function Phi (maybe multiple times), which represents Viviani's curve in a point t where t goes from 0 to 2*pi? Did I defined Phi suitable for such a derivative? I've tried diff, but it did not keep the Phi as I would need it.
If the second derivative would be Phi_d2, I need to get it's value (for example in t = 0).
How can I achieve this?
Here are three ways you can accomplish this. The first uses subs, the second uses a symfun, and the third uses complex step differentiation:
% Using subs
syms t
Phi = [cos(t) cos(t).*sin(t) sin(t)];
Phi_d2 = diff(Phi,t)
double(subs(Phi_d2,t,0))
% Using symfun
syms t
Phi(t) = [cos(t) cos(t).*sin(t) sin(t)];
Phi_d2 = diff(Phi,t)
double(Phi_d2(0))
% Using complex step differentiation
Phi = @(t)[cos(t) cos(t).*sin(t) sin(t)];
h = 2^-28;
cdiff = @(f,x)imag(f(x(:)+1i*h))/h;
Phi_d2 = cdiff(Phi,0)
You can find a function for performing first- and second-order complex step differentiation on my GitHub: cdiff. Note that complex step differentiation won't work well for higher order derivatives. It's best when one only has a non-differentiable function or needs fast numerical first derivatives.