Groovy markup builder replace the root

Question

import groovy.xml.MarkupBuilder

class XmlTest {
    static void main(def args) {
        def XmlTest s = new XmlTest()
        s.xmlTest()
    }

    def xmlTest() {
        def xml = new MarkupBuilder()
        xml.root{
            response(this.xmlClosure())
        }
    }

    def xmlClosure() {
        return {x("y")}
    }
}

The expected output is <x>y</x> I cannot modify the closure. I need to convert the closure to a XML document without adding any nodes.

Answer 1

This might help, but if you have more element types than just "x" you probably should expand on it a bit. By letting the builder write to a writer, you can take control of the result in a more controlled manner. Then, using the writer, you can extract the elements you want using a StreamingMarkupBuilder.

It's a very roundabout way, and for very large XML structures, it may not be very efficient.

I also took the liberty to omit the "response" element, as I didn't see that it made any sense. Feel free to put it back if you absolutely need it.

import groovy.xml.MarkupBuilder
import groovy.util.XmlSlurper
import groovy.xml.StreamingMarkupBuilder

class XmlTest {
    static void main(def args) {
        def sw = new StringWriter()
        println new XmlTest().xmlTest(sw)
    }

    def xmlTest(writer) {
        def builder = new MarkupBuilder(writer)        
        builder.root(xmlClosure())

        def text = new XmlSlurper().parseText(writer.toString())

        def outputBuilder = new StreamingMarkupBuilder()
        def result = outputBuilder.bind{ mkp.yield text.x }
        return result
    }

    def xmlClosure() {
        return {x("y")}
    }
}

Good luck.