For following bash statement:
tail -Fn0 /tmp/report | while true; do echo "pre"; exit; echo "past"; done
I got "pre", but didn't quit to the bash prompt, then if I input something into /tmp/report, I could quit from this script and get into bash prompt.
I think that's reasonable. the 'exit' make the 'while' statement quit, but the 'tail' still alive. If something input into /tmp/report
, the 'tail' will output to pipe, then 'tail' will detect the pipe is close, then 'tail' quits.
Am I right? If not, would anyone provide a correct interpretation?
Is it possible to add anything into 'while' statement to quit from the whole pipe statement immediately? I know I could save the pid of tail into a temporary file, then read this file in the 'while', then kill the tail. Is there a simpler way?
Let me enlarge my question. If use this tail|while in a script file, is it possible to fulfill following items simultaneously?
You can (unreliably) get away with killing the process group:
tail -Fn0 /tmp/report | while :
do
echo "pre"
sh -c 'PGID=$( ps -o pgid= $$ | tr -d \ ); kill -TERM -$PGID'
echo "past"
done
This may send the signal to more processes than you want. If you run the above command in an interactive terminal you should be okay, but in a script it is entirely possible (indeed likely) the the process group will include the script running the command. To avoid sending the signal, it would be wise to enable monitoring and run the pipeline in the background to ensure that a new process group is formed for the pipeline:
#!/bin/sh
# In Posix shells that support the User Portability Utilities option
# this includes bash & ksh), executing "set -m" turns on job control.
# Background processes run in a separate process group. If the shell
# is interactive, a line containing their exit status is printed to
# stderr upon their completion.
set -m
tail -Fn0 /tmp/report | while :
do
echo "pre"
sh -c 'PGID=$( ps -o pgid= $$ | tr -d \ ); kill -TERM -$PGID'
echo "past"
done &
wait
Note that I've replaced the while [ 1 ]
with while :
because while [ 1 ]
is poor style. (It behaves exactly the same as while [ 0 ]
).