I have been trying to create an instance of Zend\Db\TableGateway
but just can't get it right. This is what I have in my module.php
:
use Question\Model\QuestionsTable;
use Zend\Db\ResultSet\ResultSet;
use Zend\Db\TableGateway\TableGateway;
//other statements and then getServiceConfig()
public function getServiceConfig()
{
return array(
'factories' => array(
'Question\Model\QuestionsTable' => function($sm) {
$tableGateway = $sm->get('AlbumTableGateway');
$table = new QuestionsTable($tableGateway);
return $table;
},
'AlbumTableGateway' => function ($sm) {
$dbAdapter = $sm->get('Zend\Db\Adapter\Adapter');
$resultSetPrototype = new ResultSet();
$resultSetPrototype->setArrayObjectPrototype(new QuestionsTable());
return new TableGateway('questions', $dbAdapter, null, $resultSetPrototype);
},
),
);
}
This is my QuestionsTable.php
file:
namespace Question\Model;
use Zend\Db\TableGateway\TableGateway;
class QuestionsTable
{
public $usr_id;
public $title;
public $description;
public $status;
protected $tableGateway;
public function __construct(TableGateway $tableGateway)
{
$this->tableGateway = $tableGateway;
}
}
And this is the error I am getting:
Catchable fatal error: Argument 1 passed to Question\Model\QuestionsTable::__construct() must be an instance of Zend\Db\TableGateway\TableGateway,none given.
Thanks in advance.
Hi I think that you should separate the table class from the prototype class.
and as a solution you can add another class Questions in Question\Model\Questions and use it as prototype
$resultSetPrototype->setArrayObjectPrototype(new Questions()); //instead of QuestionsTable
and you can do it the same way as described in Database and models from the album tuto