bash script send email recipient from reading. txt file

I made a bash script that watches a folder and when you copy a file, it is automatically sent to a specific address.

Suppose now that the files are named as follows:

red.zip green.zip

how do I send the file to the addresses:

red.zip to red@gmail.com
green.zip to green@gmail.com

or better yet you can do by reading a txt file where email addresses are: example;

rosso.zip > to read file red.txt with inside red@gmail.com red1@gmail.com red2@gmail.com

Thank you very much

Solution

Assuming that you can actually install mutt you can use the following script as a start:

#! /bin/bash

mail_body_file="mailbody.txt"
mail_address_file_extension=".txt"

for fullname in *.zip; do
    filename="${fullname%.*}"
    address_file=$filename$mail_address_file_extension
    if [ -f $address_file ] ; then
        echo "Address file found for ZIP $fullname"
        recipients=$(cat $address_file)
        echo "Sending mail to recipients $recipients..."      
        mutt -a $fullname -- -s "Attachment $fullname" "$recipients" < $mail_body_file
        sleep 10
        echo "Done."
    else
        echo "WARNING: no address file found for ZIP $fullname"
    fi
done

Notes:

The mail client mutt will cleanly append the zip file as an attachment. @KyleBanerjee: This is not the same as just piping something into the mail!
The mail client mutt should not interfere with the mail transport agent postfix. In fact, I assume that mutt will call the sendmail compatible interface of postfix to actually send the mail.
The script currently assumes that everything is in the current directory.
The script will fail if there isn't a single .zip file in the current directory.
You will have to supply a file mailbody.txt to be used as the body of the mail.
You may want to alter the subject (see parameter after -s to mutt).
The address files must contain a semicolon seperated list of mail addresses, e.g.
```
 red@gmail.com;red1@gmail.com;red2@gmail.com
```