How to mock the "+" operator in python (specifically datetime.date + datetime.timedelta)

Question

I have working through some date mocking issues in Django, and have the final hurdle (I hope) is the following situation. I have a FakeDate class, which derives from datetime.date, which it mocks out.

The FakeDate class works as expected, however I get a problem when adding a datetime.timedelta to the FakeDate, in that it returns a genuine datetime.date, rather than the mock. This is important as elsewhere in a third party library there is an isinstance(value, datetime.date) check, which will always fail when using timedelta.

>>> import mock
>>> import datetime
>>>
>>> class FakeDate(datetime.date):
...     @classmethod
...     def today(cls):
...         return cls(1999, 12, 31)
...
>>> FakeDate.today()
FakeDate(1999, 12, 31)
>>> FakeDate(2000, 1, 1)
FakeDate(2000, 1, 1)
>>> FakeDate(1999, 12, 31) + datetime.timedelta(days=1)
datetime.date(2000, 1, 1)

I want the FakeDate + timedelta addition to return a FakeDate object rather than a datetime.date object - which I imagine involves patching the timedelta somehow - but how / where can I do this?

Answer 1

Add a __add__ method to your FakeDate() class:

class FakeDate(datetime.date):
     @classmethod
     def today(cls):
         return cls(1999, 12, 31)
     def __add__(self, other):
         res = super(FakeDate, self).__add__(other)
         return type(self)(res.year, res.month, res.day)

Demo:

>>> class FakeDate(datetime.date):
...      @classmethod
...      def today(cls):
...          return cls(1999, 12, 31)
...      def __add__(self, other):
...          res = super(FakeDate, self).__add__(other)
...          return type(self)(res.year, res.month, res.day)
... 
>>> FakeDate.today() + datetime.timedelta(days=1)
FakeDate(2000, 1, 1)

Note that you can simply delegate the actual adding to the datetime.date class here; all we need to do is convert the result back to a FakeDate() instance.