What is the quickest way to insert a pandas DataFrame into mongodb using PyMongo
?
Attempts
db.myCollection.insert(df.to_dict())
gave an error
InvalidDocument: documents must have only string keys, the key was Timestamp('2013-11-23 13:31:00', tz=None)
db.myCollection.insert(df.to_json())
gave an error
TypeError: 'str' object does not support item assignment
db.myCollection.insert({id: df.to_json()})
gave an error
InvalidDocument: documents must have only string a keys, key was <built-in function id>
df
<class 'pandas.core.frame.DataFrame'>
DatetimeIndex: 150 entries, 2013-11-23 13:31:26 to 2013-11-23 13:24:07
Data columns (total 3 columns):
amount 150 non-null values
price 150 non-null values
tid 150 non-null values
dtypes: float64(2), int64(1)
I doubt there is a both quickest and simple method. If you don't worry about data conversion, you can do
>>> import json
>>> df = pd.DataFrame.from_dict({'A': {1: datetime.datetime.now()}})
>>> df
A
1 2013-11-23 21:14:34.118531
>>> records = json.loads(df.T.to_json()).values()
>>> db.myCollection.insert(records)
But in case you try to load data back, you'll get:
>>> df = read_mongo(db, 'myCollection')
>>> df
A
0 1385241274118531000
>>> df.dtypes
A int64
dtype: object
so you'll have to convert 'A' columnt back to datetime
s, as well as all not int
, float
or str
fields in your DataFrame
. For this example:
>>> df['A'] = pd.to_datetime(df['A'])
>>> df
A
0 2013-11-23 21:14:34.118531