I have an array like
myarray = 'ABCDE'
and I want output as
required_output = [AB,BC,CD,DE,EA] ## A cyclic form of array 'ABCDE'
I used following code
for i in range(len(myarray) + 1):
a = i % len(myarray) ; b = i % len(myarray) + 2
print myarray[a : b]
result I get as
AB , BC, CD, DE, E , AB
what logic I am missing which is causing 'e' to appear instead of 'ea' and also 'ab' should not have appeared ???
Another way I found was to use a loop like this
for i in range(1,len(myarray)):
print myarray[i-1] + myarray[i]
gives output as
'EA','AB','BC','CD','DE' ## where the last element 'EA' comes in the begining
It's not too hard to see what's going wrong
>>> myarray = 'ABCDE'
>>> for i in range(len(myarray) + 1):
... a = i % len(myarray) ; b = i % len(myarray) + 2
... print a, b, myarray[a: b]
...
0 2 AB
1 3 BC
2 4 CD
3 5 DE
4 6 E
0 2 AB
There's no way you're going to get a slice like 'EA' without doing something heroic like
>>> myarray[::-4]
'EA'
The + 1 is obviously going to give you one more output than the number of items in myarray
Easy fix is something like this
>>> for i in range(len(myarray)):
... print (myarray*2)[i:i+2]
...
AB
BC
CD
DE
EA