I have data in SQL Server in the format below.
-ID ID2 status time
-1384904453 417 stop 2013-11-19 23:40:43.000
-1384900211 417 start 2013-11-19 22:30:06.000
-1384822614 417 stop 2013-11-19 00:56:36.000
-1384813810 417 start 2013-11-18 22:30:06.000
-1384561199 417 stop 2013-11-16 00:19:45.000
-1384554623 417 start 2013-11-15 22:30:06.000
-1384475231 417 stop 2013-11-15 00:26:58.000
-1384468224 417 start 2013-11-14 22:30:06.000
-1384388181 417 stop 2013-11-14 00:16:20.000
-1384381807 417 start 2013-11-13 22:30:06.000
-1384300222 417 stop 2013-11-12 23:50:11.000
-1384295414 417 start 2013-11-12 22:30:06.000
-1384218209 417 stop 2013-11-12 01:03:17.000
-1384209015 417 start 2013-11-11 22:30:06.000
What I need is to be able to show data in the following format.
-ID2 start stop
-417 2013-11-19 22:30:06.000 2013-11-19 23:40:43.000
-417 2013-11-18 22:30:06.000 2013-11-19 00:56:36.000
Is it possible to do this? I tried pivot in SQL Server but it only returns one record. Can someone help please?
You can use the PIVOT function to get the result, I would just apply the row_number() windowing function to the data so you can return multiple rows for each ID2:
select id2, start, stop
from
(
select id2, status, time,
row_number() over(partition by status
order by time) seq
from yourtable
) d
pivot
(
max(time)
for status in (start, stop)
) piv
order by start desc;
See SQL Fiddle with Demo.
You could also use an aggregate function with a CASE expression to get the final result:
select
id2,
max(case when status = 'start' then time end) start,
max(case when status = 'start' then time end) stop
from
(
select id2, status, time,
row_number() over(partition by status
order by time) seq
from yourtable
) d
group by id2, seq;