I am trying to find the union of set of sets. Specifically I want the union of the list of nodes for each key in the dictionary of networkx graphs called periodic_gs. I would like to use the reduce function as it seems reasonable to take the union of all periodic_gs[x].nodes() where x is a key of periodic_gs.
Here is my attempt:
reduce(lambda x,y: set(periodic_gs[x].nodes()).union(set(periodic_gs[y].nodes())), periodic_gs.keys(), {})
To me, this says take the union of the nodes across each graph in the dictionary. For some reason, python tells me: TypeError: unhashable type: 'dict' I do not see this TypeError, because periodic_gs.keys() is a list of the keys (they are strings but I do not see how this would matter), and when substituted in for the arguments to the lambda function will work.
What is causing the type error and how do I fix it?
You can use set.union like this:
>>> lis = [{1, 2, 3, 4}, {3, 4, 5}, {7, 3, 6}]
>>> set().union(*lis)
set([1, 2, 3, 4, 5, 6, 7])
It's possible to do this using reduce, but don't:
>>> reduce(set.union, lis)
set([1, 2, 3, 4, 5, 6, 7])
because this reduce takes quadratic time due to all the intermediate sets it builds and discards:
In [1]: from functools import reduce
In [2]: sets = [{x} for x in range(1000)]
In [3]: %timeit set().union(*sets)
40.9 µs ± 1.43 µs per loop (mean ± std. dev. of 7 runs, 10000 loops each)
In [4]: %timeit reduce(set.union, sets)
4.09 ms ± 587 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
That's a 100x slowdown on this test case, and it can easily be even worse.
For your code, this should do it:
set().union(*(x.nodes() for x in periodic_gs.values()))