This little piece of code gives Notice: Undefined index: placeno1
I know it can be fixed by using if(isset()), but I have no idea how to place this on the correct matter in this $query line.
Tried a lot, but can't get it right.
<?php
$query = mysql_query("SELECT `id` FROM `place` WHERE `placeno` = '".$_SESSION['placeno'.$i]."' LIMIT 1");
while($row = mysql_fetch_object($query)){
?>
Solution is
<?php
if(isset($_SESSION['placeno'.$i])) {
$query = mysql_query("SELECT `id` FROM `place` WHERE `placeno` = '".$_SESSION['placeno'.$i]."' LIMIT 1");
while($row = mysql_fetch_object($query)){
}
}
?>
Undefined index is a array notice. So possible notice source is 'placeno'.$i
. You need to check it on every loop.
I am assuming you are looping this code with for()
loop. That is where $i
is coming from.
<?php
if (isset($_SESSION['placeno'.$i])) {
$query = mysql_query("SELECT `id` FROM `place` WHERE `placeno` = '".$_SESSION['placeno'.$i]."' LIMIT 1");
while($row = mysql_fetch_object($query)){
}
}
?>
If it's a loop, you can stop the loop like this:
<?php
if (!isset($_SESSION['placeno'.$i])) {
break;
}
$query = mysql_query("SELECT `id` FROM `place` WHERE `placeno` = '".$_SESSION['placeno'.$i]."' LIMIT 1");
while($row = mysql_fetch_object($query)){
?>