Quickly Converting uint32_t to binary

Question

The main problem I'm having is to read out values in binary in C++ (python had some really quick/easy functions to do this)

I just need the same. So at the moment I have:

ValWord< uint32_t> data1=//[SOME READ FUNCTION]

When I use cout << data1; It gives me a number e.g 2147581953

I want this to be in binary and eventually each "bit" needs to be in its own bin including all '0's e.g:

for (int i = 31; i >= 0; i--) {
      cout << binary[i];
    }  

Would give me this 32 bit long binary number. When I've had it as a straight forwward int, I've used:

    int data[32];
    bitset<32>(N) = data1;

    for(int i=31; i >=0; i--) {
      data[i]=(bitset<32>(N[i]).to_ulong());
    }

    for (int i = 31; i >= 0; i--) {
      cout << data[i];
    }  

But this just gives me error messages. Any ideas?

Answer 1

Maybe this:

#define CPlusPlus11 0

#if CPlusPlus11
int main()
{
    std::uint32_t value(42);
    std::bitset<32> bits(value);
    std::cout << bits.to_string() << std::endl;
    // Storing integral values in the string:
    for(auto i: bits.to_string(char(0), char(1))) {
        std::cout << (int)i;
    }
    std::cout << std::endl;
    return 0;
}
#else
int main()
{
    std::uint32_t value(42);
    std::bitset<32> bits(value);
    std::cout << bits.to_string() << std::endl;
    char data[32];
    for(unsigned i = 0; i < 32; ++i) {
        data[i] = bits[i];
    }
    for(unsigned i = 32; i; --i) {
        std::cout << int(data[i-1]);
    }
    std::cout << std::endl;
    return 0;
}
#endif

Note: Your expressions bitset<32>(N) = data1 and bitset<32>(N[i]) are code smell.